Tutorial Question 1a
Main learning points
i. units conversion
ii. instantaneous acceleration at a particular time = gradient of the tangent drawn on the v-t graph at that time
iii. area under v-t graph = change in displacement or distance traveled
Tutorial Question 1b
Main learning points
i. making use of equations of motion only when acceleration is constant
ii. the importance of sign convention
Alternative solution to Question 1b (the graphical way)
Main learning points
i. units conversion
ii. instantaneous acceleration at a particular time = gradient of the tangent drawn on the v-t graph at that time
iii. area under v-t graph = change in displacement or distance traveled
Tutorial Question 1b
Main learning points
i. making use of equations of motion only when acceleration is constant
ii. the importance of sign convention
Alternative solution to Question 1b (the graphical way)
Tutorial Question 2
Main learning points i. understanding the question - reaction time vs braking time ii. making use of equations of motion only when acceleration is constant iii.importance of sign convention Alternative solution to Question 2 (the graphical way) Additional question: Will the haze condition affect reaction time or braking time? How about the angle of the road with respect to the horizontal? |
Tutorial Question 3a
Main learning points
i. value of v-t graph gives the gradient of s-t graph
ii. difference between sketching and plotting
iii.area under v-t graph gives the change in displacement
Tutorial Question 3b
Main learning points
i. gradient of v-t graph gives the value on a-t graph
ii. sharp peaks on a-t graph (infinite acceleration) appears because of change in velocity over a very short time
Main learning points
i. value of v-t graph gives the gradient of s-t graph
ii. difference between sketching and plotting
iii.area under v-t graph gives the change in displacement
Tutorial Question 3b
Main learning points
i. gradient of v-t graph gives the value on a-t graph
ii. sharp peaks on a-t graph (infinite acceleration) appears because of change in velocity over a very short time
Tutorial Question 5
Main learning points a. understanding that final velocity is the velocity of the ball just before hitting the ground b. use of equations of motion in solving questions c. the speed of ball after the rebound is less than the speed before the hitting the ground as some of the kinetic energy is converted to other forms of energy. d. displacement has a direction. Try using s = ut + 1/2at^2 to solve the question to see if you have problems with sign convention. e. skills in drawing v-t graph relating to the motion i. check the gradient which tells us the acceleration ii. check the area under the graph which tells us the displacement iii.labeling of critical points when sketching Do you really know your stuff? Extension to part (e) f. continuing with downward as positive, using the answer to part (e), sketch the displacement-time graph. g. try doing part (e) by taking upward as positive and check if you have gotten it correct. |
Tutorial Question 6
Main learning points
a. graph conversion from a-t to v-t. Video also explains how to double check whether the graphs drawn are correct.
b. graph conversion from v-t to a-t.
Main learning points
a. graph conversion from a-t to v-t. Video also explains how to double check whether the graphs drawn are correct.
b. graph conversion from v-t to a-t.
Tutorial Question 7
Please watch the thought process if you are stuck. Hint : Thought process Given up? Check the solution here. Main learning points i. draw diagrams to understand the question |
![Picture](/uploads/4/1/0/5/41051203/8900682.jpg?1418100573)
Tutorial Question 8
Main learning points
a. checking pre-defined positive direction
b. understanding v-t graph
bii. relating v-t graph to the actual motion of the bodies
c. graph conversion from v-t to s-t. Be mindful of the little details e.g. the gradient and the area under the graph.
Main learning points
a. checking pre-defined positive direction
b. understanding v-t graph
bii. relating v-t graph to the actual motion of the bodies
c. graph conversion from v-t to s-t. Be mindful of the little details e.g. the gradient and the area under the graph.
Tutorial Question 9
Main learning points a. understanding 2D projectile motion i. vertical velocity at highest point is zero ii. horizontal velocity remains the same throughout the motion iii.vertical acceleration remains 9.81 m s^-2 throughout the motion iv. horizontal acceleration is zero b. determining velocity of a point in the path i. determine the vertical component and horizontal component of the velocity at that point ii. use pythagoras theorem to determine resultant magnitude of velocity iii. use vector diagram with labeled angle to show direction of velocity c. meaning of time of flight and range |
Tutorial Question 10
a. if you have gotten 2.5 m s^-1 as your answer, you may be right! b. if you are gotten y = 0.73 x^2 as your answer, you may be right! if you are stuck, look at this hint video and try again. if you have given up or just want to double check, here is the solution |
Tutorial Question 11
Some questions to ask yourself before you proceed with this question. a. Hint: use vertical height and time taken to determine Uy, then from Uy you would be able to determine U. Try it! solution b&c. solution d&e. determining velocity at a point i. determine the vertical component and horizontal component of the velocity at that point ii. use pythagoras theorem to determine resultant magnitude of velocity iii. use vector diagram with labeled angle to show direction of velocity f(i). it is very important to know how to sketch s-t, v-t and a-t graphs of a particular motion f(ii). basics of effects of air resistance & how to sketch the sx, vx and ax graphs how to sketch the sy, vy and ay graphs |
Tutorial Question 12
This question is not so straight forward. It requires logical reasoning and workings to substantiate the conclusion. The answer to this question is that it will hit surface R. If you have problem proving, please look at this video for the guiding steps and proceed to work out the solution. This is the first step of the solution to prove that it is not going to hit P or S. How do we proceed to prove that it is not going to hit S? Hint. This is the final step of the solution to prove that it is not going to hit S. Hence conclusion is that it is going to hit R. |
Tutorial Question 13
This question may just look deceivingly difficult.
If you are stuck, look at this hint.
This is the solution.
Main learning points
i. the way to deal with solve simultaneous equations involving cosine and sine is to have one over the other to make it a tangent. This is an important skill to learn.
ii. do not be daunted by the question. Use your fundamentals and you can overcome it step by step.
This question may just look deceivingly difficult.
If you are stuck, look at this hint.
This is the solution.
Main learning points
i. the way to deal with solve simultaneous equations involving cosine and sine is to have one over the other to make it a tangent. This is an important skill to learn.
ii. do not be daunted by the question. Use your fundamentals and you can overcome it step by step.